factorise (1+x) (1+a)+b(1+x)+ab+abx
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⇒-ab(a+b) = (a+b)x(a+b+x) ➡ (a+b){x(a+b+x)+ ab) = 0
x(a+b+x)+ ab = 0
→x² + ax+bx+ ab 0
=→x(x+a) +b(x+a)=0
(x+ a)(x+b)=0
➡x + a = 0 or x +b = 0
⇒x=-a or x = -b
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