Factorise 1-x^2-2xy-y^2
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9
1-x^2-2xy-y^2
=1-(x+y)^2 (using identity (a+b)^2)
1 can be written as 1^2
(1)^2-(x+y)^2
{1-(x+y)}{1+(x+y)}
=1-(x+y)^2 (using identity (a+b)^2)
1 can be written as 1^2
(1)^2-(x+y)^2
{1-(x+y)}{1+(x+y)}
Answered by
8
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' 1 - x^2 - 2 x y - y^2 '
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= 1 - ( x^2 + 2 x y + y^2 )
= 1 - ( x + y )^2
= ( 1)^2 - ( x + y )^2
= { 1 - ( x + y ) } { 1 + (x + y ) }
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= ( 1 - x - y ) ( 1 + x + y )
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' 1 - x^2 - 2 x y - y^2 '
_______________________________
= 1 - ( x^2 + 2 x y + y^2 )
= 1 - ( x + y )^2
= ( 1)^2 - ( x + y )^2
= { 1 - ( x + y ) } { 1 + (x + y ) }
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= ( 1 - x - y ) ( 1 + x + y )
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