Question

factorise:- (1).... (x^4+4)

Answer 1

Given Equation is x^4 + 4.

It can be written as:

= > x^4 + 2x^3 - 2x^3 + 2x^2 - 4x^2 + 2x^2 - 4x + 4x + 4

= > x^4 + 2x^3 + 2x^2 - 2x^3 - 4x^2 - 4x + 2x^2 + 4x + 4

= > x^2(x^2 + 2x + 2) - 2x(x^2 + 2x + 2) + 2(x^2 + 2x + 2)

= > (x^2 - 2x + 2)(x^2 + 2x + 2).

Hope it helps!

Answer 2

⬛◼️$\bold {\huge {Solutions :-}}$ ◼️⬛



$\bold{\huge {Q: ~ x^4 + 4}}$

$\bold {It ~can~ also~ be ~written~ as :-}$

$\bold {= > x^4 + 2x^3 - 2x^3 + 2x^2 - 4x^2 }$$\bold {+ 2x^2 - 4x + 4x + 4}$

$\bold {= > x^4 + 2x^3 + 2x^2 - 2x^3 - 4x^2}$ $\bold {- 4x + 2x^2 + 4x + 4}$

$\bold {= > x^2(x^2 + 2x + 2) - 2x(x^2 + 2x + 2)}$ $\bold {+ 2(x^2 + 2x + 2)}$

$\bold {= > (x^2 - 2x + 2)(x^2 + 2x + 2)}$