Question

Factorise 1+x+xy+x2y

Answer 1

$1(1 + x) + xy(1 + x) = (1 + x)(1 + xy)$

Answer 2

Answer:

(1+x)(1+xy)

Step-by-step explanation:

In this question, we have to take the common variable from each two variables. So in 1+x+xy+x2y, we have x common in 1 and x as we consider 1 as x. And in xy and x2y, xy is common. Hence the answer is (1+x)(1+xy).

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