Question

factorise:- 1 - (. x - y)^2
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Answer 1

Answer:

sorry l don't know the answer for this question paper

Answer 2

Answer:

$= > (1 + x - y)(1 - x +y )$

Step-by-step explanation:

$since \: a {}^{2} - b {}^{2} = ( a+ b)(a -b )$

$therefore \: 1 - (x - y) {}^{2} = (1) {}^{2} - (x - y) {}^{2}$

$= > ((1 + (x - y))(1 -( x - y))$

$= > (1 + x - y)(1 - x + y)$