Question

factorise: 1.x²-23x²-14x-12​

Answer 1

Answer:

It does not have any real roots

Step-by-step explanation:

x² - 23x² - 14x - 12

= -22x² - 14x - 12

now using discriminant since the equation is a quadratic equation

b² = (-14)² = 196

4ac = 4 × (-22) × (-12) = 1056

Now,

b² - 4ac = 196 - 1056 = -860

as we know that,

if b² - 4ac > 0 then the equation have two distinct real roots

if b² - 4ac = 0 then the equation have two equal roots

if b² - 4ac < 0 then the equation have no real roots

Our equation satisfies 3rd condition

∴ it does not have any real roots