Question

Factorise :

1. x²-2ax+a²-4b²
2. 1-a²-2ab-b²

*please, give me answer in step wise.*​

Answer 1

Step-by-step explanation:

1 :

x2 – 2ax – (4b2 – a2) = 0

⇒ x2 + (2b – a)x – (2b + a)x – (4b2 – a2) = 0

⇒ x(x + 2b – a) – (2b + a)(x + 2b – a) = 0

⇒ (x + 2b – a)(x – 2b – a) = 0

⇒ (x + 2b – a) = 0, (x – 2b – a) = 0

∴ x = a − 2b, a + 2b