factorise 1.)x³-5x²-x+5
Answers
Answered by
0
Answer:
(x - 5)(x - 1)(x + 1) are the factors of x³- 5x²- x + 5
Step-by-step explanation:
Given equation is x³-5x²-x+5
We need to factorise this
Step 1 : Taking common
From the first two terms that is x³-5x², we take take x² common as it is common to both.
=> x³-5x²-x+5 = x²(x - 5) - x + 5
We take -1 common from the last two terms that is -x+5
x²(x - 5) - 1( x - 5)
Taking x-5 common, we get
(x - 5) (x² - 1)
We know that a² - b² = (a - b)(a + b)
Here, let a = x and b = 1
=> x² - 1 = (x - 1)(x + 1)
Therefore, (x - 5)(x - 1)(x + 1) are the factors of x³- 5x²- x + 5
Similar questions