Question

factorise
1] x⁴+5x²+a
2] a²+b²-c²-d²+2ab - 2cd

Answer 1

Answer:

Step-by-step explanation:

It is given that ,

a² + b² - c² - d² + 2ab - 2cd

Rearranging the terms ,

= a² + b² + 2ab - c² - d² - 2cd

= ( a² + b² + 2ab ) - ( c² + d² + 2cd )

= ( a + b )² - ( c + d )²

= [ ( a + b ) + ( c + d ) ][ ( a + b) - ( c + d ) ]

= ( a + b + c + d ) ( a + b - c - d )

For the first part please check your question once. There is something wrong in that.