Question

factorise 1 +x⁴ + x⁸​

Answer 1

Answer:

$1+x4+x81+x4+x8+x4−x41+2x4+x8−x4(1+x4)2−x2(1+x4)2−(x2)2(1+x2+x4)(1+x4+x2)(1+x2+x2+x4−x2)(1+x4−x2)(1+2x2+x4−x2)(1+x4−x2)</p><p></p><p>[(1+x2)2−x2][1+x4−x2](1+x+x2)(1−x+x2)(1−x2+x4)</p><p></p><p>$

1+x

4

+x

8

1+x

4

+x

8

+x

4

−x

4

1+2x

4

+x

8

−x

4

(1+x

4

)

2

−x

2

(1+x

4

)

2

−(x

2

)

2

(1+x

2

+x

4

)(1+x

4

+x

2

)

(1+x

2

+x

2

+x

4

−x

2

)(1+x

4

−x

2

)

(1+2x

2

+x

4

−x

2

)(1+x

4

−x

2

)

[(1+x

2

)

2

−x

2

][1+x

4

−x

2

]

(1+x+x

2

)(1−x+x

2

)(1−x

2

+x

4

)

Answer 2

1 +x⁴ + x⁸

=> (1)²+2x⁴+(x⁴)² - x⁴

=> (x⁴+1)² - (x²)²

=> (x⁴+1-x²) (x⁴+1+x²)

=> (x⁴+1-x²) (x⁴+1+2x²-x²)

=> (x⁴+1-x²) [ (x²+1)² - (x)²]

=> (x⁴+1-x²) (x²+1-x) (x²+1+x)

HOPE IT HELPS

PLEASE MARK ME BRAINLIEST ☺️