Question

Factorise:1-y²-2yz-z²

Answer 1

Answer:

1-y²-2yz-z² = (1+y+z)(1-y-z)

Step-by-step explanation:

1-y²-2yz-z²

= 1-(y²+2yz+z²)

= 1²-(y+z)²

= [1+(y+z)][1-(y+z)]

/* By algebraic identity:

a²-b² = (a+b)(a-b) */

= (1+y+z)(1-y-z)

Therefore,

1-y²-2yz-z² = (1+y+z)(1-y-z)

•••♪

Answer 2

SOLUTION:-

We have,

1- y² -2yz -z²

$= > (1) {}^{2} - ( {y}^{2} + 2yz + {z}^{2} ) \\ \\ = > ({1)}^{2} - (y + z) {}^{2} \\ \\ = > [1 - (y + z)][1 + (y + z)] \\ \\ = > (1 - y - z)(1 + y + z)$

Thank you.