Question

Factorise:100-(121p²-88pq+16q²)

Answer 1

Answer:

100-(121p^2-88pq+16q^2)

=(10)^2-{(11p)^2-2.11p.4q+(4q)^2}

=(10)^2-(11p-4q)^2

=(10+11p-4q)(10-11p+4q)

Answer 2

Answer:

thank u for give the answer....

Step-by-step explanation:

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