Factorise :- 100b2-60bc + 9c2
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a2b2−6abc+9c2
=(ab)2+2×ab×(−3c)+(−3c)2
Using a2+b2−2ab=(a−b)2
=(ab−3c)2
Step-by-step explanation:
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Answered by
0
Step-by-step Answer:
a2b2−6abc+9c2
=(ab)2+2×ab×(−3c)+(−3c)2
Using a2+b2−2ab=(a−b)2
=(ab−3c)2
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