Question

factorise: 1029-3x^3

Answer 1

Answer :

Now, 1029 - 3x³

= 3(343 - x³)

= 3(7³ - x³)

= 3(7 - x){7² + (7 × x) + x²},
using the identity a³ - b³ = (a + b)(a² + ab + b²)

= 3(7 - x)(49 + 7x + x²),
which is the required factorization.

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Answer 2

Step-by-step explanation:

NOW: (1029-3X³)

= 3(343-x³)

=. 3(7³-x³)

Using formula ( a³-b³ )= ( a-b) [a²+ab+b²]

= 3(7-x)[7²+7x+ x²]

=3(7-x)(49+7x+x²)

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