Question

Factorise 108(b+c) - 3(b+c)3

Answer 1

Answer

Given : 108a

2

−3(b−c)

2

Taking 3 as common in the given question

108a

2

−3(b−c)

2

=3[36a

2

−(b−c)

2

]

We can write it as

108a

2

−3(b−c)

2

=3[(6a)

2

−(b−c)

2

]

Based on the equation a

2

−b

2

=(a+b)(a−b)

We get,

108a

2

−3(b−c)

2

=3(6a+b−c)(6a−b+c)

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

108(b+c) - 3(b+c)3

108(b+c) - 9(b+c)

9(b+c) { 12 - 1 }

9(b+c) × 11

99(b+c)