Factorise : 108a^2-3(b-c)^2
Answers
Answered by
227
Heya !!
Here is your answer..
108a^2 - 3(b-c)^2
==> 3 [ 36a^2 - (b-c)^2 ]
==> 3 [ (6a)^2 - (b-c)^2 ]
==> 3 (6a + b - c) (6a - b - c)
Hope it helps.
Here is your answer..
108a^2 - 3(b-c)^2
==> 3 [ 36a^2 - (b-c)^2 ]
==> 3 [ (6a)^2 - (b-c)^2 ]
==> 3 (6a + b - c) (6a - b - c)
Hope it helps.
Answered by
15
Answer:
108a^2 - 3(b-c)^2
==> 3 [ 36a^2 - (b-c)^2 ]
==> 3 [ (6a)^2 - (b-c)^2 ]
==> 3 (6a + b - c) (6a - b - c)
Step-by-step explanation:
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