Question

Factorise 10a^2-20ab^2+10b^4
using identity
(a-b)^2=a^2-2ab+b^2

Answer 1

• 10 a² - 20 ab² + 10 b⁴

      = 10 a² - 10ab² - 10ab² + 10b⁴

      = 10a( a - b²) - 10b² ( a - b²)

       = (10a - 10 b²) ( a - b²)

Thank u.

Answer 2

Answer:

10(a-b^2)^2

Step-by-step explanation:

10a^2 - 20ab^2 + 10b^4

= 10(a^2 - 2ab^2 + b^4)

= 10(a - b^2)^2                   [(a-b)^2 = a^2 - 2ab^2 + b^2]