Question

factorise -10a^4x^2-15a^6x^4+20a^7x^5

Answer 1

$Given \: -10a^4x^2-15a^6x^4+20a^7x^5$

$= (5a^{4}x^{2})(-2) - (5a^{4}x^{2})(3a^{2}x^{2})+(5a^{4}x^{2})(4a^{3}x^{2})$

$= (5a^{4}x^{2})(-2-3a^{2}x^{2} + 4a^{3}x^{2})$

Therefore.,

$\red{ -10a^4x^2-15a^6x^4+20a^7x^5}$

$\green { = (5a^{4}x^{2})(-2-3a^{2}x^{2} + 4a^{3}x^{2})}$

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