factorise: 10p2q2-21pq+9
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Step-by-step explanation:
In \triangle ABC△ABC ,
The bisectors of ∠A intersects BC in D .
And ....
• AB = 18 cm
• AC = 15 cm
• BC = 22 cm
• BD = ??
Solve :
In ΔABC, AD is the bisector of ∠A ....
\frac{AB}{AC}= \frac{BD}{DC}
AC
AB
=
DC
BD
[The external bisector of an angle of a triangle divides the opposite side externally in the ratio of the sides containing the angle]
\frac{AB}{AC}= \frac{BD}{(BC - BD )}
AC
AB
=
(BC−BD)
BD
=> \frac{18}{15}= \frac{BD}{(22- BD )}
15
18
=
(22−BD)
BD
=> \frac{6}{5}= \frac{BD}{(22- BD )}
5
6
=
(22−BD)
BD
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