Question

factorise:-- 10x²-2x-9​

Answer 1

$10 {x}^{2} - 2x - 9$

$= 10( {x}^{2} - \frac{2}{10} x - \frac{9}{10} )$

$= 10(x - ( \frac{ 1 - \sqrt{91} }{10}) )(x - ( \frac{ 1 + \sqrt{91} )}{10} ))$