Question

factorise 10y (6y + 21) ÷ 5 (2y +7)

Answer 1

 10y (6y + 21) ÷ 5 (2y +7)

= 10y*3(2y+7) / 5(2y+7)
= 10y*3 / 5
= 6y

Answer 2

Answer:

The factor of $\frac{10y(6y+21)}{5(2y+7)}$ is 6y.

Step-by-step explanation:

• Factorization or factoring is defined as the breaking or decomposition of an entity into a product of another entity, or factors, which when multiplied together give the original number.
• A product in math is defined as the result of two or more numbers when multiplied together.

• A factor is a number that divides another number, leaving no remainder.
• An algebraic equation can be defined as a mathematical statement in which two expressions are set equal to each other.

It is asked to factorize $\frac{10y(6y+21)}{5(2y+7)}$

Taking 3 common in numerator i.e. $6y+21=3(2y+7)$

• In a fraction, the top number is called the numerator and the bottom number is called the denominator.

$\frac{10y*3*(2y+7)}{5(2y+7)}$

Cancelling 2y+7 and $\frac{10}{5} =2$

$=2y*3=6y$

$\frac{10y(6y+21)}{5(2y+7)}=6y$

To know more about factorization go to the following link.

https://brainly.in/question/1332401

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