Question

factorise 10y(9y + 21) ÷ 2(3y + 7)

Answer it by step by step

Answer 1

The value of 10y(9y + 21) ÷ 2(3y + 7) is "15y".

Step-by-step explanation:

We have,

10y(9y + 21) ÷ 2(3y + 7)

= $\dfrac{10y(9y + 21)}{2(3y + 7)}$

=  $\dfrac{10y\times\ 3(3y + 7)}{2(3y + 7)}$

= $\dfrac{10y\times\ 3}{2}$

= 5y × 3

= 15y

Hence, the value of 10y(9y + 21) ÷ 2(3y + 7) is 15y.

Answer 2

After factorisation, it gives 15y.

Step-by-step explanation:

Since we have given that

10y(9y + 21) ÷ 2(3y + 7)

So, it becomes,

$\dfrac{10y(9y+21)}{2(3y+7)}\\\\=\dfrac{10y\times 3(3y+7)}{2(3y+7)}\\\\=\dfrac{10y}\times 3}{2}\\\\=15y$

Hence, after factorisation, it gives 15y.

# learn more:

Solve this equation step by step

3y^2-10y+3

https://brainly.in/question/1749383