Question

factorise 111xsquare+37x-28​

Answer 1

Step-by-step explanation:

$\huge11 {x}^{2} + 37x - 28 \:$

for factorisation (by spllting the middle term) can be done by :-

let ax²+bx+c be the equation

then to do splliting we multiply a by c and obtain ac (with sign) now we have to split ac into two number such that the sum become equal to b

so for the equation 11X²+37X-28

(-11×28) can be written as (-7×44)

and -7+44=37

so 11X²+(44-7)X-28

11X²+(44-7)X-2811X²+44X-7X-28

11X²+(44-7)X-2811X²+44X-7X-2811X(X+4)-7(X+4)

11X²+(44-7)X-2811X²+44X-7X-2811X(X+4)-7(X+4)(X+4)(11X-7)

so the answer is

$\huge(x + 4)(11x - 7)$