Question

Factorise : 12 (2x-3y)^2 - 16 (3y-2x)

Answer 1

12(2x-3y)²+16(2x-3y). [as minus is taken out]
[2x-3y](4){3(2x-3y)+4}
this is the factorization.


hope helps u mark as brainliest

Answer 2

Answer:

$Factors \: of \:\\ 12(2x-3y)^{2}-16(3y-2x)\\= 4(3y-2x)(9y-6x-4)$

Step-by-step explanation:

$Given \\12(2x-3y)^{2}-16(3y-2x)$

$=3\times 4(3y-2x)^{2}-4\times 4(3y-2x)$

$=4(3y-2x)[3(3y-2x)-4]$

$=4(3y-2x)(9y-6x-4)$

Therefore,

$Factors \: of \:\\ 12(2x-3y)^{2}-16(3y-2x)\\= 4(3y-2x)(9y-6x-4)$

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