factorise 12 (a+b)^2-(a+b)-35
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Answer:
(4a+4b-7)(3a+3b+5)
Step-by-step explanation:
12(a+b)²-(a+b)-35
=12(a+b)²-21(a+b)+20(a+b)-35
=3(a+b)[4(a+b)-7]+5[4(a+b)-7]
=[4(a+b)-7][3(a+b)+5]
=(4a+4b-7)(3a+3b+5)
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