Question

factorise:
12(x-2)^2 - 25(x-2)(y+1) + 12(y+1)^2

Answer 1

Heya!
here's your answer!
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$let \: (x - 2) \: be \: a \:$
$and \: (y + 1) \: be \: b$
$therefore \\ the \: equation \: will \: be \: >$
$= > 12 {a}^{2} + 25ab + 12 {b}^{2}$
$= > 12 {a}^{2} + 16ab + 9ab \: + 12 {b}^{2}$
$= > 4a(3a + 4b) + 3b(3a + 4b)$
$= > (4a + 3b) \: (3a + 4b)$
further , you need to substitute the value of a and b in this equation above.

further calculation after this is provided in the picture.

the final answer is:-

$= > (4x + 3y - 5) \: (3x + 4y - 2)$
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$hope \: this \: helps \: you \:$

Answer 2

Answer:

hope it's help u to understand it