factorise 12 y square + 8 Y - 20
Answers
Answered by
10
12y2+8y-20
12y2-12y+20y-20
12y(y-1)+20(y-1)
(12y+20),(y-1)
12y+20=0
12y=-20
y=-20/12
y=-5/3
or
y-1=0
y=1
Answered by
7
Hey
Here is your answer,
12y^2 + 8y - 20 = 0
12y^2 - 12y + 20y - 20 = 0
12y (y-1) + 20 (y-1) = 0
(12y + 20) (y-1) = 0
12y + 20 = 0
Y = -20/12 = -5/3
Y-1 = 0
Y=1
Hope it helps you!
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