Factorise :
121 b²-88bc +16 c²
Answers
Answered by
0
Answer:
Answer
(11b+4c)
2
121b
2
+88bc+16c
2
=(11b)
2
+2×11b×4c+(4c)
2
=(11b+4c)
2
Answered by
0
Answer:
121b² -44bc-44bc+16c²=0
11b(11b-4c) -4c (11b-4c)=0
(11b-4c)(11b-4c)
★(11b-4c)² = Answer
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