Math, asked by ramtekevedanti, 14 days ago

Factorise :
121 b²-88bc +16 c²​

Answers

Answered by ritabratamazumder6
0

Answer:

Answer

(11b+4c)

2

121b

2

+88bc+16c

2

=(11b)

2

+2×11b×4c+(4c)

2

=(11b+4c)

2

Answered by poonamrathore504
0

Answer:

121b² -44bc-44bc+16c²=0

11b(11b-4c) -4c (11b-4c)=0

(11b-4c)(11b-4c)

★(11b-4c)² = Answer

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