Question

Factorise:
121a^2 - 88ab+16b^2
I am getting wrong answer.. please help out.

Answer 1

Answer :

121 a² - 88ab + 16 b²

⇒ (11a)² - 2 * 11a * 4b + (4b)²

⇒ ( 11a - 4b )²

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IDENTITY USED:

• a² - 2ab + b² = (a - b)²

Answer 2

we have

${121a}^{2} - 88ab + {16b}^{2} \\ = > {(11a)}^{2} - 2 \times 11a \times 4b + {(4b)}^{2} \\ = > {(11a - 4b)}^{2}$

hope this helps.

plz mark as brainliest answer