Question

factorise 121a⁴b³c - 55a³b² + 66a²b³c​

Answer 1

Answer:

121a⁴b³c - 55a³b² + 66a²b³c

Answer 2

2x

2x 2

2x 2 −7x−15

Step-by-step explanation:

ANSWER

ANSWERWe have,

ANSWERWe have,2x

ANSWERWe have,2x 2

ANSWERWe have,2x 2 −7x−15

ANSWERWe have,2x 2 −7x−15=2x

ANSWERWe have,2x 2 −7x−15=2x 2

ANSWERWe have,2x 2 −7x−15=2x 2 −10x+3x−15

ANSWERWe have,2x 2 −7x−15=2x 2 −10x+3x−15=2x(x−5)+3(x−5)

ANSWERWe have,2x 2 −7x−15=2x 2 −10x+3x−15=2x(x−5)+3(x−5)=(x−5)(2x+3)

ANSWERWe have,2x 2 −7x−15=2x 2 −10x+3x−15=2x(x−5)+3(x−5)=(x−5)(2x+3)

ANSWERWe have,2x 2 −7x−15=2x 2 −10x+3x−15=2x(x−5)+3(x−5)=(x−5)(2x+3)