Question

factorise 121b - 88bc + 16c

Answer 1

By using identity that is :
(a-b) the whole square we can solve it.
so here is your answer
(11b - 4c)(11c - 4c)
Hope it helps.

Answer 2

$(11b) { }^{2} - 11b \times4c + (4c) {}^{2}$
$(11c - 4c) {}^{2}$
is this helpful