Question

Factorise:- 121b²–88bc+16c²

Class 8
Maths

Answer 1

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121b²-88bc+16c²

= (11b)²-2×11b×4c+(4c)²

= (11b-4c)²

Using identity: (x-y)² = x²-2xy+y²

Answer 2

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121b²-88bc+16c²

= (11b)²-2×11b×4c+(4c)²

= (11b-4c)2

Using identity: (x-y)² = x²-2xy+y²