Math, asked by himanshijain64, 1 year ago

factorise 121k^2-88kl+16l^2

Answers

Answered by 9975383932

3

Answer:

It is the third identity of maths a^2-2ab+b^2

Step-by-step explanation:

121k^2-88kl+16l^2

= (11k^2)-2 (11k)(4l)+(4l^2)

= (11k-4l)^2

Answered by pravatidas64593

5

Answer:

hiiiii buddy

Step-by-step explanation:

here is ur answer

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