Question

factorise: 121x²-289​

Answer 1

Answer:

(11x+17)(11x-17)  

Step-by-step explanation:

121x^2-289

=11^2 * x^2 - 17^2

=(11x+17)(11x-17)          [identity used :- a^2 -b^2=(a+b)(a-b)]

HOPE THIS HELPS YOU!!

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Answer 2

$121x²-289=0$

$121x²=289$

$x^2=\frac{+289}{-121}$

$x=\frac{+17}{11}$

$\:\:\:\:\:or$

$x=\frac{-17}{11}$