Question

factorise 125-a³b³+10-2ab


pls.. bata do bhai ​

Answer 1

Answer:

The given expression is:

a^3a

3

- 125 - 2a + 10

We have to find the factorisation of a^3a

3

- 125 - 2a + 10.

Solution:

∴ a^3a

3

- 125 - 2a + 10

= a^3a

3

- 5^35

3

- 2a + 10

Using the algebraic identity:

a^3a

3

- b^3b

3

= (a - b)( a^2a

2

+ ab + b^2b

2

)

= (a - 5)( a^2a

2

+ 5a + 5^25

2

) - 2a + 10

= (a - 5)( a^2a

2

+ 5a + 2525 ) - 2(a - 5)

Taking (a - 5) as common, we get

= (a - 5)[( a^2a

2

+ 5a + 2525 ) - 2]

= (a - 5)( a^2a

2

+ 5a + 2525 - 2)

= (a - 5)( a^2a

2

+ 5a + 23)

∴ The factorisation of a^3a

3

- 125 - 2a + 10 = (a - 5)( a^2a

2

+ 5a + 23)

Thus, the factorisation of a^3a

3

- 125 - 2a + 10 is "(a - 5)( a^2a

2

+ 5a + 23)".

Step-by-step explanation:

Hope it will help you.