Question

factorise - (125)x^3 - 64 y^3​

Answer 1

Step-by-step explanation:

(5x)3−64y3(5x)3-64y3

Rewrite 64y364y3 as (4y)3(4y)3.

(5x)3−(4y)3(5x)3-(4y)3

Since both terms are perfect cubes, factor using the difference of cubes formula, a3−b3=(a−b)(a2+ab+b2)a3-b3=(a-b)(a2+ab+b2) where a=5xa=5x and b=4yb=4y.

(5x−(4y))((5x)2+5x(4y)+(4y)2)

hope it is helpful for you

Answer 2

Answer:

=125x^3 -64Y^3

(5x)^3 -( 4y)^3

(5x-4y). ( 25x^2 +16y^2 + 20xy )