factorise 125a³- 8b³
Answers
Answered by
9
It can be written as (5a)^3 - (2b)^3
Using the identity,
a^3 - b^3 = (a-b)(a^2 + ab + b^2)
we get,
125a^3 - 8b^3 = (5a - 2b)(25a^2 + 10ab + 4b^2)
Answered by
0
On factoring 125a³- 8b³ we will get (5a-2b)(25a² +10ab +4b²)
Given problem:
Factorise 125a³- 8b³
Solution:
Given 125a³- 8b³
As we know
125 = 5³ ⇒ 125a³ = (5a)³
8 = 2³ ⇒ 8b³ = (2b)³
From above,
125a³- 8b³ = (5a)³- (2b)³
We know that from algebraic identities
(a³-b³) = (a-b)(a²+ab +b²)
Take a = 5a and b = 2b and apply above formula
(5a)³- (2b)³ = (5a-2b)[ (5a)² +(5a)(2b) + (2b)² ]
= (5a-2b)(25a² +10ab +4b²)
⇒ 125a³- 8b³ = (5a-2b)(25a² +10ab +4b²)
Therefore,
On factoring 125a³- 8b³ we will get (5a-2b)(25a² +10ab +4b²)
#SPJ2
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