Question

factorise 125a³ - 8b³.​

Answer 1

Answer:

$125a^3-8b^3=(5a-2b)(25a^2+10ab+4b^2)$

Step-by-step explanation:

Using the identity - $x^3-y^3=(x-y)(x^2+xy+y^2)$ .

$125a^3-8b^3=(5a)^3-(2b)^3$

⇒$125a^3-8b^3=(5a-2b)((5a)^2+(5a)(2b)+(2b)^2)$

⇒$125a^3-8b^3=(5a-2b)(25a^2+10ab+4b^2)$ .