factorise 125x^3-24underroot3y^3
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Answer:
125x
3
+27y
3
+8z
3
−90xyz
(5x)
3
+(3y)
3
+(2z)
3
−5x.3y.2z×3
a
3
+b
3
+c
3
−3abc=(a+b+c)(a
2
+b
2
+c
2
−ab−bc−ca)
(5x+3y+2z)(25x
2
+9y
2
+4z
2
−15xy−6yz−10xz)
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