Question

Factorise 125x cube--64ycube


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Answer 1

Answer:

(5x - 4y)(25(x^2) + 20xy + 4(y^2))

Step-by-step explanation:

(x^3) - (y^3) = (x - y)((x^2) + xy + (y^2))

this is an identity

here x = 5x and y = 4y

125(x^3) - 64(y^3)

(5x - 4y)(25(x^2) + 20xy + 4(y^2))

hope this helps

Answer 2

Step-by-step explanation:

$125x {}^{3} - 64y {}^{3} \\ write \: the \: elements \: in \: cube \: form \: \\ (5x) {}^{3} - (4y) {}^{3} \\ \\ using \: identity \:: \\ a {}^{3} - b {}^{3} = (a - b)(a {}^{2} + b {}^{2} + ab) \\ (5x - 4y)((5x) {}^{2} + (4y) {}^{2} + 5x \times 4y) \\ (5x - 4y)(25x {}^{2} + 16y {}^{2} + 20xy)$