Math, asked by poojagarg447, 5 months ago

factorise 128x⁴y + 250xy⁴​

Answers

Answered by mysticd
1

 Given \: algebraic \: expression :

 128x^{4}y + 250xy^{4}

 = \blue{ ( 2xy ) }\times 64x^{3} + \blue{ ( 2xy ) }\times 125y^{3}

 = 2xy( 64x^{3} + 125y^{3} )

 = 2xy[ (4x)^{3} + (5y^{3}) ]

 = 2xy \{ (4x+5y)[(4x)^{2} - (4x)(5y) + (5y)^{2}]\}

 = 2xy(4x+5y)(16x^{2} - 20xy + 25y^{2})

Therefore.,

 \red{ Factors \: of \: 128x^{4}y + 250xy^{4} }

 \green {= 2xy(4x+5y)(16x^{2} - 20xy + 25y^{2})}

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