factorise 12a^2+7a-10 please help!!!
Answers
Answer:
Step-by-step explanation:
Factoring 12a2-7a-10
The first term is, 12a2 its coefficient is 12 .
The middle term is, -7a its coefficient is -7 .
The last term, "the constant", is -10
Step-1 : Multiply the coefficient of the first term by the constant 12 • -10 = -120
Step-2 : Find two factors of -120 whose sum equals the coefficient of the middle term, which is -7 .
-120 + 1 = -119
-60 + 2 = -58
-40 + 3 = -37
-30 + 4 = -26
-24 + 5 = -19
-20 + 6 = -14
-15 + 8 = -7 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -15 and 8
12a2 - 15a + 8a - 10
Step-4 : Add up the first 2 terms, pulling out like factors :
3a • (4a-5)
Add up the last 2 terms, pulling out common factors :
2 • (4a-5)
Step-5 : Add up the four terms of step 4 :
(3a+2) • (4a-5)
Which is the desired factorization
Final result :
(4a - 5) • (3a + 2)
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