factorise 12a²+31ab+20b²
Answers
Answered by
0
Answer:
(3a+4b)(4a+5b)
Step-by-step explanation:
12a²+31ba+20b
Find one factor of the form ka^{m}+nka
m
+n, where ka^{m}ka
m
divides the monomial with the highest power 12a^{2}12a
2
and nn divides the constant factor 20b^{2}20b
2
. One such factor is (3a+4b) (3a+4b). Factor the polynomial by dividing it by this factor.
Answered by
0
Answer:
12a²+31ab+20b²
=12a²+(16+15)ab+20b²
==12a²+16ab+15ab+20b²
=4a(3a+4b)+5b(3a+4b)
=(3a+4b)(4a+5b)
Step-by-step explanation:
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