Math, asked by bhardwajkhushi15090, 23 hours ago

Factorise
12a2b+15ab2
..​

Answers

Answered by MrFire07
4

Answer: 3ab (4a + 5b)

Explanation: We have

12a²b = 2 × 2 × 3 × a × a × b.

15ab² = 3 × 5 × a × b × b.

The two terms have 3, a, and b as common factors.

Therefore,

12a²b + 15ab²

= (3 × a × b × 2 × 2 × a) + (3 × a × b × 5 × b)

= 3 × a × b × [(2 × 2 × a) + (5 × b)]

...(combining the terms)

= 3ab × (4a + 5b)

= 3ab (4a + 5b)

...(required factor form)

Concept: Factorisation by taking out common factors

Answered by walt2006disney
1

Pls check the attached images for the solution

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