Factorise
12a2b+15ab2
..
Answers
Answered by
4
Answer: 3ab (4a + 5b)
Explanation: We have
12a²b = 2 × 2 × 3 × a × a × b.
15ab² = 3 × 5 × a × b × b.
The two terms have 3, a, and b as common factors.
Therefore,
12a²b + 15ab²
= (3 × a × b × 2 × 2 × a) + (3 × a × b × 5 × b)
= 3 × a × b × [(2 × 2 × a) + (5 × b)]
...(combining the terms)
= 3ab × (4a + 5b)
= 3ab (4a + 5b)
...(required factor form)
Concept: Factorisation by taking out common factors
Answered by
1
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