Factorise 12cy+20c-15-9y completely.
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SOLUTION STEPS
12cy+20c−15−9y
Do the grouping 12cy+20c−15−9y=(12cy+20c)+(−15−9y), and factor out 4c in the first and −3 in the second group.
4c(3y+5)−3(3y+5)
Factor out common term 3y+5 by using distributive property.
(3y+5)(4c−3)
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