Math, asked by biswajeetsahoo849, 9 months ago

factorise 12pqr(6p^2-13pq+6q^2)÷6pq(2p-3q)​

Answers

Answered by jainnishank592004
0

Answer:

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Answered by Pragyanshurana
0

Answer:

12pqr(6p^2-13pq+6q^2)÷6pq(2p-3p)

step by step explanation

multiply by 12 pqr and 6 pq

(72p^3qr-156p^2q^2r+72pq^3r) ÷ (12p^2q-18p^2q)

(72p^3qr-156p^2q^2r+72pq^3r)

(12p^2q-18p^2q).

divide this digit

6pr-156qr+4pq^3r.

This is the answer

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