factorise 12pqr(6p^2-13pq+6q^2)÷6pq(2p-3q)
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Answer:
12pqr(6p^2-13pq+6q^2)÷6pq(2p-3p)
step by step explanation
multiply by 12 pqr and 6 pq
(72p^3qr-156p^2q^2r+72pq^3r) ÷ (12p^2q-18p^2q)
(72p^3qr-156p^2q^2r+72pq^3r)
(12p^2q-18p^2q).
divide this digit
6pr-156qr+4pq^3r.
This is the answer
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