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factorise 12r²+25r+12=0​

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Answered by Anonymous
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Answer:

Factoring 12r2-25r+12

The first term is, 12r2 its coefficient is 12 .

The middle term is, -25r its coefficient is -25 .

The last term, "the constant", is +12

Step-1 : Multiply the coefficient of the first term by the constant 12 • 12 = 144

Step-2 : Find two factors of 144 whose sum equals the coefficient of the middle term, which is -25 .

-144 + -1 = -145

-72 + -2 = -74

-48 + -3 = -51

-36 + -4 = -40

-24 + -6 = -30

-18 + -8 = -26

-16 + -9 = -25 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -16 and -9

12r2 - 16r - 9r - 12

Step-4 : Add up the first 2 terms, pulling out like factors :

4r • (3r-4)

Add up the last 2 terms, pulling out common factors :

3 • (3r-4)

Step-5 : Add up the four terms of step 4 :

(4r-3) • (3r-4)

Which is the desired factorization

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