Question

factorise 12x^2-19x - 10
exam haj plz jaldi batao​

Answer 1

Answer:

Factoring 12x2-19x-10

The first term is, 12x2 its coefficient is 12 .

The middle term is, -19x its coefficient is -19 .

The last term, "the constant", is -10

Step-1 : Multiply the coefficient of the first term by the constant 12 • -10 = -120

Step-2 : Find two factors of -120 whose sum equals the coefficient of the middle term, which is -19 .

-120 + 1 = -119

-60 + 2 = -58

-40 + 3 = -37

-30 + 4 = -26

-24 + 5 = -19 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -24 and 5

12x2 - 24x + 5x - 10

Step-4 : Add up the first 2 terms, pulling out like factors :

12x • (x-2)

Add up the last 2 terms, pulling out common factors :

5 • (x-2)

Step-5 : Add up the four terms of step 4 :

(12x+5) • (x-2)

Which is the desired factorization

Final result :

(x - 2) • (12x + 5)