Question

factorise 12x^2+36x^2y+27y^2x^2​

Answer 1

Answer:

$\bf\:12x^2+36x^2y+27x^2y^2=3x^2(3y+2)^2$​

Step-by-step explanation:

Factorise

$12x^2+36x^2y+27x^2y^2$​

$\text{Taking }3x^2 \text{common from each term}$

$=3x^2[4+12y+9y^2]$​

$=3x^2[9y^2+12y+4]$​

$=3x^2[(3y)^2+2(3y)(2)+2^2]$​

using

$\boxed{a^2+2ab+b^2=(a+b)^2}$

$=3x^2(3y+2)^2$​

$\implies\:\boxed{12x^2+36x^2y+27x^2y^2=3x^2(3y+2)^2}$​