factorise 12x^3+4x^2-3x-1
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Answered by
22
Here is the answer;
12x^3+4x^2-3x-1
=12x^3-3x+4x^2-1
=3x(4x^2-1)+4x^2-1
=(4x^2-1)(3+1)
=(2x+1)(2x-1)4
=4(2x+1)(2x-1)
basudev88:
But there is a little mistake. On the fourth step there should be (3x+1).I hope you understood it.
Answered by
9
Answer
(x-2) and (X+4)(X+5) are two factors of.........
after that factorise (x² + 9x + 20) by middle term split
- then after you get answer (X+4)(X+5)
- first factor we get = ( x-2 )
- and second = (X+4)(X+5)
Therefore, two factors are ( x-2 ) and (X+4)(X+5)
Hope that this Will help you
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